Integrand size = 17, antiderivative size = 31 \[ \int \sec ^4(a+b x) \tan ^2(a+b x) \, dx=\frac {\tan ^3(a+b x)}{3 b}+\frac {\tan ^5(a+b x)}{5 b} \]
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Time = 0.02 (sec) , antiderivative size = 31, normalized size of antiderivative = 1.00, number of steps used = 3, number of rules used = 2, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.118, Rules used = {2687, 14} \[ \int \sec ^4(a+b x) \tan ^2(a+b x) \, dx=\frac {\tan ^5(a+b x)}{5 b}+\frac {\tan ^3(a+b x)}{3 b} \]
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Rule 14
Rule 2687
Rubi steps \begin{align*} \text {integral}& = \frac {\text {Subst}\left (\int x^2 \left (1+x^2\right ) \, dx,x,\tan (a+b x)\right )}{b} \\ & = \frac {\text {Subst}\left (\int \left (x^2+x^4\right ) \, dx,x,\tan (a+b x)\right )}{b} \\ & = \frac {\tan ^3(a+b x)}{3 b}+\frac {\tan ^5(a+b x)}{5 b} \\ \end{align*}
Time = 0.11 (sec) , antiderivative size = 56, normalized size of antiderivative = 1.81 \[ \int \sec ^4(a+b x) \tan ^2(a+b x) \, dx=-\frac {2 \tan (a+b x)}{15 b}-\frac {\sec ^2(a+b x) \tan (a+b x)}{15 b}+\frac {\sec ^4(a+b x) \tan (a+b x)}{5 b} \]
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Time = 0.15 (sec) , antiderivative size = 42, normalized size of antiderivative = 1.35
method | result | size |
derivativedivides | \(\frac {\frac {\sin ^{3}\left (b x +a \right )}{5 \cos \left (b x +a \right )^{5}}+\frac {2 \left (\sin ^{3}\left (b x +a \right )\right )}{15 \cos \left (b x +a \right )^{3}}}{b}\) | \(42\) |
default | \(\frac {\frac {\sin ^{3}\left (b x +a \right )}{5 \cos \left (b x +a \right )^{5}}+\frac {2 \left (\sin ^{3}\left (b x +a \right )\right )}{15 \cos \left (b x +a \right )^{3}}}{b}\) | \(42\) |
risch | \(-\frac {4 i \left (15 \,{\mathrm e}^{6 i \left (b x +a \right )}-5 \,{\mathrm e}^{4 i \left (b x +a \right )}+5 \,{\mathrm e}^{2 i \left (b x +a \right )}+1\right )}{15 b \left ({\mathrm e}^{2 i \left (b x +a \right )}+1\right )^{5}}\) | \(55\) |
norman | \(\frac {-\frac {8 \left (\tan ^{3}\left (\frac {b x}{2}+\frac {a}{2}\right )\right )}{3 b}-\frac {16 \left (\tan ^{5}\left (\frac {b x}{2}+\frac {a}{2}\right )\right )}{15 b}-\frac {8 \left (\tan ^{7}\left (\frac {b x}{2}+\frac {a}{2}\right )\right )}{3 b}}{\left (\tan ^{2}\left (\frac {b x}{2}+\frac {a}{2}\right )-1\right )^{5}}\) | \(66\) |
parallelrisch | \(\frac {-\frac {8 \left (\tan ^{7}\left (\frac {b x}{2}+\frac {a}{2}\right )\right )}{3}-\frac {16 \left (\tan ^{5}\left (\frac {b x}{2}+\frac {a}{2}\right )\right )}{15}-\frac {8 \left (\tan ^{3}\left (\frac {b x}{2}+\frac {a}{2}\right )\right )}{3}}{b \left (\tan \left (\frac {b x}{2}+\frac {a}{2}\right )-1\right )^{5} \left (\tan \left (\frac {b x}{2}+\frac {a}{2}\right )+1\right )^{5}}\) | \(72\) |
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Time = 0.29 (sec) , antiderivative size = 39, normalized size of antiderivative = 1.26 \[ \int \sec ^4(a+b x) \tan ^2(a+b x) \, dx=-\frac {{\left (2 \, \cos \left (b x + a\right )^{4} + \cos \left (b x + a\right )^{2} - 3\right )} \sin \left (b x + a\right )}{15 \, b \cos \left (b x + a\right )^{5}} \]
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\[ \int \sec ^4(a+b x) \tan ^2(a+b x) \, dx=\int \sin ^{2}{\left (a + b x \right )} \sec ^{6}{\left (a + b x \right )}\, dx \]
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Time = 0.24 (sec) , antiderivative size = 26, normalized size of antiderivative = 0.84 \[ \int \sec ^4(a+b x) \tan ^2(a+b x) \, dx=\frac {3 \, \tan \left (b x + a\right )^{5} + 5 \, \tan \left (b x + a\right )^{3}}{15 \, b} \]
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Time = 0.33 (sec) , antiderivative size = 26, normalized size of antiderivative = 0.84 \[ \int \sec ^4(a+b x) \tan ^2(a+b x) \, dx=\frac {3 \, \tan \left (b x + a\right )^{5} + 5 \, \tan \left (b x + a\right )^{3}}{15 \, b} \]
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Time = 0.08 (sec) , antiderivative size = 25, normalized size of antiderivative = 0.81 \[ \int \sec ^4(a+b x) \tan ^2(a+b x) \, dx=\frac {{\mathrm {tan}\left (a+b\,x\right )}^3\,\left (3\,{\mathrm {tan}\left (a+b\,x\right )}^2+5\right )}{15\,b} \]
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